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Please answer this Calculus webwork question about differential equations:

Please answer this Calculus webwork question about differential equations:-example-1
User Kev Price
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Answer:

a)


4ydy = xdx


2 {y}^(2) = (1)/(2) {x}^(2) + c


{y}^(2) = (1)/(4) {x}^(2) + c


{y}^(2) - (1)/(4) {x}^(2) = c

b)

c = 4, so


{y}^(2) = (1)/(4) {x}^(2) + 4


y = - \sqrt{ (1)/(4) {x}^(2) + 4}


y = - \frac{ \sqrt{ {x}^(2) + 16} }{2}

User Olivier S
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