Hello!
To find the equation of the line that passes through the points (0,-8) and (4,-3), we can use the slope-intercept form of the equation:
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, find the slope (m) of the line using the formula:
m = (y2 - y1)/(x2 - x1)
where (x1, y1) = (0,-8) and (x2, y2) = (4,-3).
m = (-3 - (-8))/(4 - 0) = 5/4
Now that we have the slope (m), we can use the point-slope form of the equation to find the equation of the line:
y - y1 = m(x - x1)
where (x1, y1) = (0,-8) and m = 5/4.
y - (-8) = (5/4)(x - 0)
Simplify the equation to get the slope-intercept form:
y + 8 = (5/4)x
y = (5/4)x - 8
Therefore, the equation of the line that passes through the points (0,-8) and (4,-3) is y = (5/4)x - 8.