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In a nuclear bomb, 6.5 x 10 12 J of energy are released. How much matter was converted into energy?

User Cnrhgn
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2 Answers

20 votes
20 votes

Answer:

Below

Step-by-step explanation:

e = mc^2 <=== solve for 'm'

m = e / c^2

= 6.5 x 10^12 / (3 x 10^8)^2

m = 7.22 x 10^-5 kg

User JD Allen
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20 votes
20 votes

Answer:

Hope this helps ;) don't forget to rate this answer !

Step-by-step explanation:

To determine the amount of matter that was converted into energy in a nuclear bomb, you would need to know the mass of the matter that was converted and the speed of light in a vacuum, c.

The relationship between the amount of energy released, E, the mass of the matter, m, and the speed of light is given by the equation E = mc², where c is the speed of light.

Therefore, to find the mass of the matter that was converted into energy, you can rearrange this equation to solve for m:

m = E/c²

Plugging in the values given in the problem, we get:

m = (6.5 x 10^12 J)/(3 x 10^8 m/s)²

= (6.5 x 10^12 J)/(9 x 10^16 m²/s²)

= (6.5 x 10^12 J)/(9 x 10^16 m²/s²)

= 7.22 x 10^-5 kg

This is the minimum amount of mass that was converted into energy in the nuclear bomb.

I hope this helps! Let me know if you have any other questions.

User Golam
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