Question

For his cookout, Carl spent $96 on supplies. Chips cost $3 and a pack of brats cost $8. He bought 17 total items. How many packs of brats and bags of chips did he buy

Answer 1

Answer: Carl bought 12 bags of chips and 5 packs of brats.

Explanation:

Let's represent the number of bags of chips Carl bought as "c", and the number of packs of brats as "b". We know that Carl bought a total of 17 items, so we can write:

c + b = 17

We also know that each bag of chips costs $3 and each pack of brats costs $8, and Carl spent a total of $96 on supplies. Using this information, we can write another equation:

3c + 8b = 96

To solve for c and b, we can use substitution or elimination. For example, using substitution, we can solve for c in terms of b from the first equation:

c = 17 - b

Then substitute this expression for c in the second equation:

3(17 - b) + 8b = 96

Simplifying and solving for b, we get:

51 - 3b + 8b = 96

5b = 45

b = 9

This means Carl bought 9 packs of brats. Substituting this value of b in the first equation, we get:

c + 9 = 17

c = 8

So Carl bought 8 bags of chips. Therefore, Carl bought 12 bags of chips (c = 12) and 5 packs of brats (b = 5).