Question

A nonconducting rod with a uniformly distributed charge

+Q. The rod forms a half-circle with radius R and produces an
electric field of magnitude Earc at its center of curvature P. If
the arc is collapsed to a point at distance R from P (Fig. b),
what is the magnitude of the electric field at P?

Answer 1

It will be same as the length of arc

Step-by-step explanation:

See we can see that the magnitude of force is equal to the magnitude of the arc so it is equal