Question

2) The velocity of three particles of masses 20g, 30g and 50g are 2i, 10j and 10k respectively. The velocity of the centre of mass the three particle) is​

Answer 1

The velocity of the center of mass (COM) is given by:

v_COM = (m1v1 + m2v2 + m3v3) / (m1 + m2 + m3)

where m1, m2, and m3 are the masses of the particles, and v1, v2, and v3 are their velocities.

Substituting the given values, we get:

v_COM = (0.02 kg)(2i m/s) + (0.03 kg)(10j m/s) + (0.05 kg)(10k m/s) / (0.02 kg + 0.03 kg + 0.05 kg)

v_COM = (0.04i + 0.3j + 0.5k) m/s

Therefore, the velocity of the center of mass of the three particles is (0.04i + 0.3j + 0.5k) m/s.