Question

According to this balanced equation, how many grams of water (H₂O) form in this reaction? KOH 56.11 g HCI 36.46 g A. 167.12 grams OB. 94.20 grams C. 54.90 grams OD. 18.02 grams KCI 74.55 g H₂O ? SUBMIT​

Answer 1

The balanced chemical equation for the reaction between KOH and HCl is:

KOH + HCl -> KCl + H2O

From the equation, we can see that 1 mole of KOH reacts with 1 mole of HCl to produce 1 mole of water.

To determine the amount of water formed, we first need to calculate the number of moles of HCl and KOH used in the reaction:

moles of HCl = mass / molar mass = 36.46 g / 36.46 g/mol = 1.0 mol
moles of KOH = mass / molar mass = 56.11 g / 56.11 g/mol = 1.0 mol

Since the reaction is 1:1 between KOH and HCl, we know that 1.0 mol of water is formed.

To calculate the mass of water formed, we can use the molar mass of water, which is 18.02 g/mol:

mass of water = moles of water x molar mass of water = 1.0 mol x 18.02 g/mol = 18.02 g

Therefore, the answer is OD. 18.02 grams.