Question

an aluminum wing on a passenger jet is 31 m long when temperature is 29°C. At what temperature would the wing be 4cm (.04m) shorter?​

Answer 1

T = 43,451.16°c

Step-by-step explanation:

decrease in length = alpha ×original length × change in temperature

31m - 0.04m = 30.96m

30.96m = 2.3 ×10^-5 k^-1 × 31m × ( T - 302k), T temperature final

30.96m = 7.13 ×10^-4 × ( T - 302k)

T - 302k = 30.96m / 7.13 ×10^ -4 m/k

T - 302k = 43,422.16k

T = 43,724.16 k

T = 43,451.16°c