Question

Felicia is deciding on her schedule for next semester. She must take each of the following classes: English 102, Spanish 102, History 102, and College Algebra. If there are 15 sections of English 102, 9 sections of Spanish 102, 12 sections of History 102, and 13 sections of College Algebra, how many different possible schedules are there for Felicia to choose from? Assume there are no time conflicts between the different classes.

Answer 1

Okay, here are the steps to solve this problem:

* There are 15 sections of English 102 to choose from

* There are 9 sections of Spanish 102 to choose from

* There are 12 sections of History 102 to choose from

* There are 13 sections of College Algebra to choose from

So for English 102 Felicia has 15 options, for Spanish 102 she has 9 options, for History 102 she has 12 options, and for College Algebra she has 13 options.

By the Fundamental Principle of Counting, the total number of possible schedules is:

15 * 9 * 12 * 13 = 16,920

Therefore, the total number of possible schedules for Felicia is 16,920