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What volume of a 25M solution can be prepared with 28.5g of K2S molar mass 110.26g

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Answer:

10.34 mL

Step-by-step explanation:

The molar mass of K2S is 110.26g/mol.

Number of moles of K2S = mass / molar mass

Number of moles of K2S = 28.5g / 110.26g/mol = 0.2586 mol

Now, we can use the definition of molarity to calculate the volume of the solution that can be prepared.

Molarity = number of moles / volume of solution (in liters)

Rearranging the equation, we get:

Volume of solution = number of moles / molarity

Volume of solution = 0.2586 mol / 25 mol/L = 0.010344 L = 10.34 mL

Therefore, 10.34 mL of a 25M solution of K2S can be prepared from 28.5g of K2S.

User Thomas Glick
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