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4 votes
Special right triangle

Special right triangle-example-1
User Sblandin
by
7.8k points

1 Answer

3 votes

Answer:

s = 5
√(6)

Explanation:

using the cosine ratio in the right triangle and the exact value

cos30° =
(√(3) )/(2) , then

cos30° =
(adjacent)/(hypotenuse) =
(s)/(10√(2) ) =
(√(3) )/(2) ( cross- multiply )

2s = 10
√(2) ×
√(3) = 10
√(6) ( divide both sides by 2 )

s = 5
√(6)

User Walter A
by
8.5k points

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