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If 7.50 g of ammonia hydroxide react, how many moles of ammonia will be produced?

User Ltackett
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The balanced chemical equation for the reaction of ammonia hydroxide (NH4OH) producing ammonia (NH3) is:

NH4OH → NH3 + H2O

The equation shows that 1 mole of NH4OH produces 1 mole of NH3.

To determine the number of moles of NH3 produced from 7.50 g of NH4OH, we need to first calculate the molar mass of NH4OH:

NH4OH = 1 x 14.01 (atomic mass of N) + 4 x 1.01 (atomic mass of H) + 1 x 16.00 (atomic mass of O) = 35.05 g/mol

Next, we can use the following formula to calculate the number of moles:

moles = mass / molar mass

moles of NH4OH = 7.50 g / 35.05 g/mol = 0.214 mol

Since 1 mole of NH4OH produces 1 mole of NH3, the number of moles of NH3 produced is also 0.214 mol.

Therefore, 7.50 g of NH4OH produces 0.214 moles of NH3.

User DaFoot
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