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34 votes
34 votes
Help I’m slow ❗️❗️❗️LOTS OF POINTS OFFERED❗️❗️❗️

Help I’m slow ❗️❗️❗️LOTS OF POINTS OFFERED❗️❗️❗️-example-1
User Aniket Navlur
by
2.8k points

2 Answers

20 votes
20 votes

Answer:

x -5y = -20

Explanation:

The equation written in the slope intercept form of the line is

y = 1/5x + 4 Subtract 1/5x from both sides

--1/5 x + y = 4 Multiply through by -5

x -5y = -20

The standard form of a line is Ax + By = C

A, B, and C must all be integers and A needs to be positive.

slope intercept form

y = mx + b. The m is the slope. There are two points graphed. If you start with the point on the left, to get to the point on the right, you had to go down 2 and right 10. That would give a slope of -2/10 which would simplify to -1/5. the b is where the line crosses the y axis: 4.

User Tanwer
by
2.8k points
20 votes
20 votes

Answer:

x + 5y = 20

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = (- 5, 5) and (x₂, y₂ ) = (5, 3) ← 2 points on the line

m =
(3-5)/(5-(-5)) =
(-2)/(5+5) =
(-2)/(10) = -
(1)/(5)

the line crosses the y- axis at (0, 4 ) ⇒ c = 4

y = -
(1)/(5) x + 4 ← equation in slope- intercept form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and A, B are integers

y = -
(1)/(5) x + 4 ( multiply through by 5 to clear the fraction )

5y = - x + 20 ( add x to both sides )

x + 5y = 20 ← equation in standard form

User Mario Menger
by
2.5k points
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