In the given reaction:
MnO2 + 4HCl -> MnCl2 + 2H2O + Cl
(a) The substance that is oxidized is hydrogen chloride (HCl).
(b) The oxidizing agent is manganese dioxide (MnO2), which accepts electrons from HCl to form MnCl2.
(c) The substance that is reduced is MnO2, which gains electrons from HCl to form MnCl2.
(d) The reducing agent is hydrogen chloride (HCl), which donates electrons to MnO2 to form MnCl2.