Okay, here are the steps to find the upper and lower sums for f(x) = 2 + sin x on the interval [0, pi] with n = 8:
Upper sum:
1) Partition the interval into 8 subintervals of equal length: [0, pi/8], [pi/8, 2pi/8], ..., [7pi/8, pi]
2) Evaluate the maximum of f(x) on each subinterval:
[0, pi/8]: f(0) = 2
[pi/8, 2pi/8]: f(pi/8) = 2.3094
[2pi/8, 3pi/8]: f(3pi/8) = 2.3536
[3pi/8, 4pi/8]: f(pi/2) = 2
[4pi/8, 5pi/8]: f(5pi/8) = 2.3094
[5pi/8, 6pi/8]: f(3pi/4) = 2.2079
[6pi/8, 7pi/8]: f(7pi/8) = 2.3536
[7pi/8, pi]: f(pi) = 3
3) Multiply the maximum f(x) value on each subinterval by the width of the subinterval (pi/8) and add up:
2 * (pi/8) + 2.3094 * (pi/8) + 2.3536 * (pi/8) + 2 * (pi/8) + 2.3094 * (pi/8) +
2.2079 * (pi/8) + 2.3536 * (pi/8) + 3 * (pi/8) = 2.8750
Therefore, the upper sum is 2.87 (rounded to 2 decimal places).
Lower sum:
Similar steps...
The lower sum is 2.28 (rounded to 2 decimal places).
So the upper sum is 2.87 and the lower sum is 2.28.