Answer:
16400g
Step-by-step explanation:
The amount of Calcium nitrate {Ca(NO3)2} that will be needed can be calculated as follows:
Molarity (M) = number of moles (n) ÷ volume (L)
According to this question, molarity = 0.2M, volume = 500L
number of moles = molarity × volume
number of moles (n) = 0.2 × 500
n = 100moles
Using mole = mass/molar mass
Molar mass of Ca(NO3)2 = 40 + {14 + 16(3)}2
= 40 + (14 + 48)2
= 40 + 62(2)
= 40 + 124
= 164g/mol
Mass = mole × molar mass
mass = 100 × 164
mass = 16400g of Ca(NO3)2