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Calcium nitrate is a compound commonly used as a plant fertilizer in agriculture and also in

wastewater treatment facilities. Let's suppose you need to prepare a 0.2 molar (0.2 M)

solution of calcium nitrate to spray a crop field. You will need to prepare 500 Liters to have

enough of this solution to spray the entire field. How much calcium nitrate will you need?

1 Answer

3 votes

Answer:

16400g

Step-by-step explanation:

The amount of Calcium nitrate {Ca(NO3)2} that will be needed can be calculated as follows:

Molarity (M) = number of moles (n) ÷ volume (L)

According to this question, molarity = 0.2M, volume = 500L

number of moles = molarity × volume

number of moles (n) = 0.2 × 500

n = 100moles

Using mole = mass/molar mass

Molar mass of Ca(NO3)2 = 40 + {14 + 16(3)}2

= 40 + (14 + 48)2

= 40 + 62(2)

= 40 + 124

= 164g/mol

Mass = mole × molar mass

mass = 100 × 164

mass = 16400g of Ca(NO3)2

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