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A pool of water has a rectangular base of 5 m by 10 m and the water is 6 m deep. What is the pressure on the base of the pool taken g = 10m/ss

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The pressure at the base of the pool is equal to the weight of the water above it divided by the area of the base.

The weight of the water can be calculated using its mass and acceleration due to gravity (g).

Mass of water = density x volume
Density of water = 1000 kg/m^3 (at 4°C)
Volume of water = base area x height = 5 m x 10 m x 6 m = 300 m^3

Therefore, mass of water = 1000 kg/m^3 x 300 m^3 = 300000 kg

The weight of the water = mass x g = 300000 kg x 10 m/ss = 3,000,000 N

The area of the base is 5 m x 10 m = 50 m^2

Therefore, the pressure on the base of the pool is:

Pressure = Weight of water / Area of base = 3,000,000 N / 50 m^2 = 60,000 N/m^2

So, the pressure on the base of the pool is 60,000 N/m^2 when g is assumed to be 10m/ss.
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