Question

two veritces of right triangle PQR are shown on the coordiante [plane below.what is the length. in units, of side PQ.vertex R is located at (3,-2). PART Bwhat is the area, in square units. of triangle PQR?show or explain how you know

Answer 1

PART A: We are missing the coordinate of vertex P, so we can't determine the length of side PQ without that information. Please let me know if you have the coordinate of vertex P, and I'd be happy to help you find the length of side PQ.

PART B: To find the area of triangle PQR, we can use the formula:

Area = (1/2) * base * height

We can use the two given vertices to find the length of the base (PQ) and height (PR) of the triangle. Let's assume that vertex P has coordinates (x, y).

Using the distance formula, we can find the length of PQ:

PQ = sqrt[(3 - x)^2 + (-2 - y)^2]

Using the distance formula, we can also find the length of PR:

PR = sqrt[(3 - x)^2 + (-2 - y)^2]

To find the area of triangle PQR, we can plug these values into the area formula:

Area = (1/2) * PQ * PR

Since PQ and PR have the same length, we can simplify the equation to:

Area = (1/2) * PQ^2

We can use the formula we found earlier for PQ to calculate the area of triangle PQR.