Register

In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth. A 90 B 4 C -4.4 D 4.4

In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth. A 90 B 4 C -4.4 D 4.4
182k views
4 votes
In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth.

A 90
B 4
C -4.4
D 4.4

User Shalah
by
8.6k points

1 Answer

3 votes
The answer is B

If you want proof on how I got it comment!
User Mussawir Ahmad Paul
by
7.9k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!