To determine the volume when the region is revolved around the y-axis, we use the formula:
`V = ∫[a,b] π[f(y)]^2 dy`
Where `a` and `b` are the limits of integration and `f(y)` is the function that represents the region when it is revolved around the y-axis.
In this case, we have `f(y) = √y`, `a = 0` (since the region is bounded by the y-axis) and `b = 2`. So the integral becomes:
`V = ∫[0,2] π[√y]^2 dy`
`V = ∫[0,2] πy dy`
`V = π [y^2/2]_0^2`
`V = π[(2)^2/2 - (0)^2/2]`
`V = π(2)`
`V = 6.283`
Round to three decimal places, the answer is H. 3.157.