Question

hydraulic fluid is flowing through a dcv at a flow rate of 114 l/min and experiences a 1,241 kpa pressure drop as the fluid flows through it. the fluid has a specific gravity of 0.89 and a specific heat of 2 kj/kg degrees c. find the temperature rise in degrees c in the fluid as it passes through the valve.

Answer 1

To calculate the temperature rise (ΔT) of the hydraulic fluid as it passes through the valve, we can use the following formula:

ΔT = (P / (ρ * C * Q)) * 1000

where:
P = pressure drop (in kPa)
ρ = density of the fluid (in kg/m³)
C = specific heat of the fluid (in J/kg°C)
Q = volumetric flow rate (in m³/s)

First, we need to convert the given flow rate from liters per minute to cubic meters per second:

Q = 114 L/min = 0.114 m³/s

Next, we need to calculate the density (ρ) of the fluid:

ρ = specific gravity * density of water
= 0.89 * 1000 kg/m³
= 890 kg/m³

Now we can substitute the given values into the formula:

ΔT = (1241 / (890 * 2 * 0.114)) * 1000
= 61.2°C

Therefore, the temperature of the hydraulic fluid will rise by approximately 61.2 degrees Celsius as it passes through the valve.