To calculate the amount of Cu that can be produced from 3.0 g of NaCl, we need to first write and balance the chemical equation for the reaction between NaCl and Cu:
2NaCl + Cu → CuCl2 + 2Na
From the balanced equation, we can see that 2 moles of NaCl react with 1 mole of Cu to produce 1 mole of CuCl2 and 2 moles of Na.
To determine the amount of Cu produced, we need to calculate the number of moles of NaCl in 3.0 g:
mass of NaCl = 3.0 g
molar mass of NaCl = 58.44 g/mol
moles of NaCl = mass/molar mass = 3.0 g / 58.44 g/mol = 0.051 mol
Now we can use the stoichiometry of the balanced chemical equation to determine the number of moles of Cu produced:
1 mole of Cu is produced from 2 moles of NaCl
moles of Cu = (0.051 mol NaCl) / (2 mol NaCl/1 mol Cu) = 0.026 mol Cu
Finally, we can use the molar mass of Cu to convert the number of moles to grams:
molar mass of Cu = 63.55 g/mol
mass of Cu = moles of Cu x molar mass of Cu = 0.026 mol x 63.55 g/mol = 1.68 g
Therefore, 1.68 grams of Cu can be produced from 3.0 g of NaCl.