Question

Calculate the molarity of 0.300 mol of Na2S in 1.75 L of solution.

Calculate the molarity of 31.3 g of MgS in 955 mL of solution

Answer 1

Molarity[Na2S] = 0.1714

Molarity[Mgs] = 0.5811

Step-by-step explanation:

Given:

0.300 mol [Na2S in 1.75 L]

31.3 g [MgS in 955 mL]

Find:

Molarity

Computation:

Molarity = Number of mole / volume in liter

Molarity[Na2S] = 0.300 / 1.75

Molarity[Na2S] = 0.1714

Molar mass of Mgs = 56.38 g/mol

Number of mole = 31.3 / 56.38

Number of mole = 0.555

Molarity[Mgs] = Number of mole / volume in liter

Molarity[Mgs] = [0.555 / 955]1000

Molarity[Mgs] = 0.5811