Explanation:
solution:
given,
no. of red balls [n(R)] = 3
no. of white balls [n(W)] = 5
no. of green balls [n(G)] = 10
no. of sample events [n(S)] = 3+5+10 = 18
no. of white or green ball [n(WUG)] = 5+10 = 15
no. of favourable events [n(E)] = 15
probability of favourable events [P(E)] = ?
We know,
P(E) = n(E) / n(S)
= 15/18
= 5/6
Therefore if a ball is chosen at random, the probability that it is either white or green is 5/6.