Question

a box contains 3 red balls, 5 white balls, and 10 green balls. if a ball is chosen at random, what is the probability that it is either white or green?

Answer 1

Explanation:

solution:

given,

no. of red balls [n(R)] = 3

no. of white balls [n(W)] = 5

no. of green balls [n(G)] = 10

no. of sample events [n(S)] = 3+5+10 = 18

no. of white or green ball [n(WUG)] = 5+10 = 15

no. of favourable events [n(E)] = 15

probability of favourable events [P(E)] = ?

We know,

P(E) = n(E) / n(S)

= 15/18

= 5/6

Therefore if a ball is chosen at random, the probability that it is either white or green is 5/6.