Answer:
To determine the force exerted on your hand, we can use the impulse-momentum theorem which states that the change in momentum of an object equals the impulse exerted on it. The impulse is the product of the force and the time of contact. Therefore, we have:
Initial momentum = m * v = 0 (since your hand is initially at rest)
Final momentum = m * vf (where vf is the final velocity of the ball after being caught)
Change in momentum = Final momentum - Initial momentum = m * vf
Impulse = F * t (where F is the force exerted on your hand)
By the impulse-momentum theorem, we have:
m * vf = F * t
Solving for F, we get:
F = m * vf / t
Given, m = 0.168 kg, v = 16 m/s, and t = 0.025 s
Final velocity, vf = 0 m/s (since the ball comes to rest after being caught)
Substituting the values, we get:
F = 0.168 kg * 0 m/s / 0.025 s
F = 0 N
Therefore, the force exerted on your hand when catching a 0.168 kg ball moving at 16 m/s in 0.025 s is 0 N.
Step-by-step explanation: