Answer:
a. 6.0 m/s to the right
b. 168 J
c. 72 J
d. 96 J
Step-by-step explanation:
a.
(3.0 kg)(10 m/s) + (1.0 kg)(-6.0 m/s) = (3.0 + 1.0 kg)v
24 kg·m/s = (4.0 kg)v
v = (24 kg·m/s)/(4.0 kg) = 6.0 m/s to the right
b.
KEbefore = 1/2(3.0 kg)(10.0 m/s)² + 1/2(1.0 kg)(-6 m/s)² = 150 J + 18 J = 168 J
c.
KEafter = 1/2(4 kg)(6.0 m/s)² = 72 J
d.
ΔKE = 168 J - 72 J = 96 J
96 J of KE converted to thermal energy as a result of the collision