Question

Calculate the bond energy in the ionic compound Nacl if the bond length is 2.36x10^-10m

Answer 1

The bond energy for NaCl with a bond length of 2.36x10^-10m cannot be calculated precisely with the given information, as additional factors like the Madelung constant and the dielectric constant are required to determine the lattice energy.

Step-by-step explanation:

The question asks to calculate the bond energy of an ionic compound, specifically sodium chloride (NaCl), given the bond length is 2.36x10-10m. To determine the bond energy of NaCl, you would need additional data such as the charges of the ions, the Madelung constant, and the dielectric constant (permittivity) for the medium in which NaCl exists. This bond energy is related to the lattice energy or the dissociation energy, which is the energy required to separate a mole of the solid ionic compound into its separate gaseous ions.

Unfortunately, the provided dissociation energy of NaCl mentioned is 4.26 eV, which refers to the energy required to break the bond between a single pair of ions (not the entire mole). To convert this to per mole, we would use Avogadro's number, but since this specific conversion isn't described in the details given, we can't proceed accurately without the full lattice energy calculations, which include the Madelung constant and other factors.

Answer 2

This question is incomplete, the complete complete question is;

Coulomb's law for the energy of interaction between two charged ions;

E = Ke × q1q2/r

Coulomb's constant Ke = 2.31 × 10⁻²⁸ J.m.

Calculate the bond energy in the ionic compound NaCl if the bond length is 2.36 × 10⁻¹⁰m

Answer:

the bond energy is -9.788 × 10⁻¹⁹ J

Step-by-step explanation:

Given the data in the question;

Ke = 2.31 × 10⁻²⁸ J.m which is the same as; Ke = 2.31 × 10⁻²⁸ Nm L/c²

ionic compound NaCl;

q1 = charge on Na in NaCl = Na⁺ = + 1C

q2 = charge on Cl in NaCl = Cl⁻ = - 1C

given that bond length r is 2.36 × 10⁻¹⁰m

E = Ke × q1q2/r

we substitute

E = 2.31 × 10⁻²⁸ × (+1 × -1) / 2.36 × 10⁻¹⁰

E = -2.31 × 10⁻²⁸ / 2.36 × 10⁻¹⁰

E = -9.788 × 10⁻¹⁹ J { The negative sign means Attraction in ions }

Therefore, the bond energy is -9.788 × 10⁻¹⁹ J