Question

A mixture of plaster contains cement, lime and sand in the ration 1:2:3

I) in how many pans of this mixture are there 24 pans of lime?
II) how many pans of sand are there in 48 pans of this mixture?

Answer 1

I) The ratio of cement, lime, and sand in the mixture is 1:2:3. Therefore, for every 2 parts of lime, there is one part of cement and three parts of sand. If we have 24 parts of lime, then we can calculate the other parts as follows:

Cement = (24/2) = <<24/2=12>>12 pans
Sand = (24/3) = <<24/3=8>>8 pans

Therefore, there are 12 pans of cement and 8 pans of sand in this mixture.

II) If we have 48 pans of this mixture, then we can calculate the amount of sand as follows:

The ratio of cement, lime, and sand in the mixture is 1:2:3. Therefore, for every 6 parts of the mixture (1+2+3), there are three parts of sand. If we have 48 pans of the mixture, then we can calculate the number of parts as follows:

Number of parts = (48/6) = <<48/6=8>>8

Therefore, there are 3 x 8 = <<3*8=24>>24 pans of sand in 48 pans of this mixture.

Answer:
I) There are 12 pans of cement and 8 pans of sand in this mixture.
II) There are 24 pans of sand in 48 pans of this mixture.