Answer:
Step-by-step by steo
Total number of students = n(P∪M)=100
Number of students who passed in physics= n(P)=55
Number of students who passed in maths= n(M)=67
Number of students who passed both physics and maths=n(P∩M)
⇒n(P∪M)=n(P)+n(M)−n(P∩M)
⇒100=55+67−n(P∩M)
⇒n(P∩M)=122−100
⇒n(P∩M)=22
Step - 2 : Find number of students who passed only in physics
Number of students passed in physics = 55
Number of students passed in physics and maths both = 22
∴Number of students passed only in physics = 55−22=33