The equation y = 2x^2 + 8 is in the form of y = ax^2 + bx + c, where a = 2, b = 0, and c = 8.
The axis of symmetry is given by the formula:
x = -b / 2a
Substituting the values of a and b into the formula, we get:
x = -0 / 4 = 0
Therefore, the axis of symmetry is x = 0.
To find the vertex, we substitute the value of x = 0 into the equation:
y = 2x^2 + 8
y = 2(0)^2 + 8
y = 8
Therefore, the vertex is at the point (0, 8).