Answer:
We can use the transformer equation to solve this problem. The transformer equation states that the ratio of voltages is equal to the inverse of the turns ratio:
Vp / Vs = Ns / Np
where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of turns in the primary coil, and Ns is the number of turns in the secondary coil.
(a) To find the voltage supplied from the transformer, we can use the transformer equation and solve for Vs:
Vs = Vp (Ns / Np)
The turns ratio is given as 13:1, which means that Ns / Np = 1 / 13. Therefore,
Vs = (120 V) (1 / 13)
Vs = 9.23 V
The voltage supplied from the transformer is 9.23 V (rms).
(b) To find the current supplied from the transformer, we can use the fact that power is conserved in a transformer. That is, the power delivered to the primary coil is equal to the power delivered to the secondary coil. Therefore,
Ip Vp = Is Vs
where Ip is the primary current, Is is the secondary current, and we have assumed ideal conditions with no losses. Rearranging this equation to solve for Is, we get:
Is = Ip (Vp / Vs)
The primary voltage is 120 V (rms). To find the primary current, we can use the fact that power is equal to voltage times current, or P = VI. The tape player draws 0.35 A from the house outlet, which means the power delivered to the primary coil is:
P = VI = (120 V) (0.35 A) = 42 W
Since the transformer is ideal and there are no losses, the power delivered to the secondary coil is also 42 W. Therefore, the current supplied from the transformer is:
Is = Ip (Vp / Vs) = (42 W) / (9.23 V)
Is = 4.55 A (rms)
The current supplied from the transformer is 4.55 A (rms).
(c) The power delivered to the tape player is equal to the power delivered to the secondary coil of the transformer, which is 42 W. Therefore, the power delivered to the tape player is 42 W.