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A work done of 50 μJ happen to a charge that is 6 nC. Calculate the voltage.

1 Answer

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Answer:

V = 8333.33 volts

Step-by-step explanation:

We know that the work done (W) in joules is equal to the product of the charge (Q) in coulombs and the voltage (V) in volts, i.e.

W = QV

Rearranging the above equation, we get

V = W/Q

We are given that the work done (W) is 50 μJ, which is equal to 50 x 10^-6 joules.

The charge (Q) is 6 nC, which is equal to 6 x 10^-9 coulombs.

Substituting the values, we get

V = (50 x 10^-6) / (6 x 10^-9)

V = 8333.33 volts

Therefore, the voltage is 8,333.33 volts (rounded to two decimal places).
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