Question

A wallet contains 34 notes, all of which are either $5 or $10 notes. If it amounts to $235, how many $10 notes are there?

Answer 1

For this question, you can use the simultaneous equation to solve this problem.

Equation 1 reads: x + y = 34. (There are 34 notes in total.)

Equation 2: 5x + 10y = 235 (The notes are worth a total of $235.)

To find x in terms of y, we can apply equation 1:

x = 34 - y

When we use this expression to replace x in equation 2, we obtain:

5(34 - y) + 10y = 235

By condensing and figuring out y, we get at:

y = 15

There are 15 $10 bills in the wallet as a result.

Answer 2

Let's assume that the number of $5 notes in the wallet is x, and the number of $10 notes is y.

According to the problem, we know that:

- x + y = 34 (since the wallet contains a total of 34 notes)
- 5x + 10y = 235 (since the total amount of money in the wallet is $235)

We can use the first equation to solve for x in terms of y:

x = 34 - y

Substituting this expression for x into the second equation, we get:

5(34 - y) + 10y = 235

Simplifying and solving for y, we get:

y = 15

Therefore, there are 15 $10 notes in the wallet.