Question

A rectangle loop with a length of 3 mm and width of 6 mm is positioned in a uniform magnetic field of magnitude 0.5 N/C so that the plane of the loop makes an angle of 75° with the magnetic field. Find the flux passing through the rectangle loop.

Answer 1

Answer:

flux = 2.34 x 10^-6 Wb

Step-by-step explanation:

The magnetic flux through a loop is given by the product of the magnetic field and the area of the loop, multiplied by the cosine of the angle between the normal to the plane of the loop and the magnetic field.

In this case, the magnitude of the magnetic field is given as 0.5 N/C. However, we assume that this value refers to the electric field (which is measured in newtons per coulomb), instead of the magnetic field. Therefore, we will assume that the magnitude of the magnetic field is actually 0.5 T.

The area of the rectangle loop is given by the product of its length and width, i.e.,

A = (3 mm) x (6 mm) = 18 mm^2

Converting this to SI units, we get:

A = 18 x 10^-6 m^2

The angle between the plane of the loop and the magnetic field is given as 75°. Therefore, the cosine of this angle is:

cos(75°) = 0.259

Putting all these values together, we get:

flux = B * A * cos(75°)
flux = (0.5 T) * (18 x 10^-6 m^2) * 0.259
flux = 2.34 x 10^-6 Wb

Therefore, the magnetic flux passing through the rectangle loop is 2.34 x 10^-6 Weber (Wb).