Since cone A and cone B are mathematically similar, their corresponding dimensions are proportional. Let the height of cone A be h_a and the height of cone B be h_b, and let the radius of cone A be r_a and the radius of cone B be r_b. Then, we have:
h_b / h_a = r_b / r_a (1)
The ratio of the volumes of cone A to cone B is 27:8, so we have:
(1/3) * π * r_a^2 * h_a / [(1/3) * π * r_b^2 * h_b] = 27/8
Simplifying this equation using Equation (1), we get:
r_b^2 / r_a^2 = 27/8 * h_b / h_a = 27/8 * r_b / r_a
Multiplying both sides by r_a^2, we get:
r_b^2 = 27/8 * r_a^2
Taking the square root of both sides, we get:
r_b = (3/2) * r_a
Substituting this relationship into the formula for the surface area of cone A, we get:
π * r_a * (r_a + √(h_a^2 + r_a^2))
Substituting r_b = (3/2) * r_a and simplifying, we get:
π * r_a * (2.5 * r_a + √(h_b^2 + (2.5 * r_a)^2)) = 297
Simplifying this equation using Equation (1), we get:
π * r_b * (2.5 * r_b + √(h_a^2 + (2.5 * r_b)^2)) = (27/8) * 297
Simplifying this equation, we get:
π * r_b * (2.5 * r_b + √(h_b^2 + (2.5 * r_b)^2)) = 132
Therefore, the surface area of cone B is 132 cm².