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The perimeter of a rectangle is 52 cm. If its width is 2 cm more than one-third of its length, find the dimensions of rectangle.

User Jdizzle
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Let's call the length of the rectangle "L" and the width "W".

From the problem, we know that:

- The perimeter of a rectangle is 2(L + W), so 2(L + W) = 52 (since "The perimeter of a rectangle is 52 cm")
- The width is 2 cm more than one-third of the length, so W = (1/3)L + 2 (since "Its width is 2 cm more than one-third of its length")

We can use substitution to solve for one of the variables. Substituting the second equation into the first equation, we get:

2(L + (1/3)L + 2) = 52

Simplifying the left side, we get:

2(4/3 L + 2) = 52

Multiplying both sides by 1/2, we get:

4/3 L + 2 = 26

Subtracting 2 from both sides, we get:

4/3 L = 24

Multiplying both sides by 3/4, we get:

L = 18

Now that we know L, we can use the second equation to solve for W:

W = (1/3)L + 2
W = (1/3)(18) + 2
W = 8

Therefore, the dimensions of the rectangle are 18 cm by 8 cm.
User Martin Mihaylov
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