Question

a gas in a cylinder is exerting a pressure of 400Pa on the walls.if the walls have an area of 3m^2, what is the total outward force (thrust) on them?​

Answer 1

Answer:

F = 1200 N

Step-by-step explanation:

The pressure exerted by a gas is defined as the force exerted per unit area of the walls of the container. It can be expressed mathematically as:

P = F/A

where P is the pressure, F is the force, and A is the area of the walls.

We are given that the pressure exerted by the gas is 400 Pa and the area of the walls is 3 m^2. Therefore, we can rearrange the above expression to find the force as:

F = P * A

Substituting the given values, we get:

F = 400 Pa * 3 m^2
F = 1200 N

Therefore, the total outward force (thrust) on the walls is 1200 N.

Answer 2

The total outward force (thrust) on the walls of the cylinder can be calculated using the formula:

Force = Pressure * Area

where Pressure is the pressure exerted by the gas on the walls of the cylinder, and Area is the area of the walls.

Substituting the given values, we get:

Force = 400 Pa * 3 m^2 = 1200 N

Therefore, the total outward force (thrust) on the walls of the cylinder is 1200 N.