Question

Given the equation X=10m+(5m/s^2) t^2, find the change in positiin at t1=1s, t2=2s
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Answer 1

To find the change in position between t1=1s and t2=2s, we need to calculate the displacement (change in position) caused by acceleration between these two times.

First, we can find the position at t1=1s:

X1 = 10m + (5m/s^2) (1s)^2 = 15m

Next, we can find the position at t2=2s:

X2 = 10m + (5m/s^2) (2s)^2 = 30m

The change in position between t1 and t2 is simply the difference between X2 and X1:

ΔX = X2 - X1 = 30m - 15m = 15m

Therefore, the change in position between t1=1s and t2=2s is 15 meters.