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What is the angle between a wire carrying an 8. 2 -a current and the 1. 2 -t field surrounding the wire if a portion the wire, length 47 cm, experiences a magnetic force of 2. 25 n?

User Leo Arad
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1 Answer

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Answer:

We can use the formula for the magnetic force on a wire:

F = BIL sin(theta)

Where:

F = magnetic force on the wire = 2.25 N

B = magnetic field strength = 1.2 T

I = current in the wire = 8.2 A

L = length of the wire segment = 47 cm = 0.47 m

We can rearrange this formula to solve for the angle theta:

theta = sin^(-1)(F / BIL)

Substituting the given values:

theta = sin^(-1)(2.25 N / (1.2 T * 8.2 A * 0.47 m))

theta = sin^(-1)(0.331)

theta = 19.5 degrees

Therefore, the angle between the wire carrying the current and the magnetic field is approximately 19.5 degrees.

Step-by-step explanation:

User Gurg Hackpof
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