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A 35-ft long solid steel rod is subjected to a load of 8,000 lb. This load causes the rod to stretch 0.266 in. The modulus of elasticity of the steel is 30,000,000 psi. Determine the diameter of the rod (precision of 0.00)

User Amcdrmtt
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Answer:

The diameter of the rod can be determined using the following formula:

Step-by-step explanation:

d = sqrt(4L / (pi * E * delta))

where:

d = diameter of the rod

L = length of the rod = 35 ft

E = modulus of elasticity of the steel = 30,000,000 psi

delta = elongation of the rod = 0.266 in

First, we need to convert the length of the rod and elongation to inches to maintain consistency with the units of E:

L = 35 ft * 12 in/ft = 420 in

delta = 0.266 in

Substituting the given values into the formula:

d = sqrt(4 * 420 / (pi * 30,000,000 * 0.266))

d = 0.615 in (rounded to 0.01)

Therefore, the diameter of the steel rod is 0.62 inches (rounded to 0.01).

User Milliams
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