Question

A sample of copper with a mass of 50. 0 grams

goes from an initial temperature of 22. 0°C to a

final temperature of 41. 6°C. Calculate the change

in thermal energy, and state whether it was gained

or lost

Answer 1

Answer: The copper gained 377.3 J/g

Explanation: Formula is: q=MC(delta t)

Q= heat in J/g

M= mass

C= Specific heat

Delta T (ΔT)= final temp minus initial temp (the difference in temp)

q=x

m=50.0 g

c= 0.385 J/g

ΔT= 41.6-22=19.6

q=(50)(.385)(19.6)

q= 377.3 J/g