123k views
5 votes
Write the equation in standard form for the circle passing through (–8,4) centered at the origin.

User Keymap
by
7.3k points

1 Answer

5 votes

Answer:

x² + y² = 80

Explanation:

Pre-Solving

We are given that a circle has the center at the origin (the point (0,0)) and passes through the point (-8,4).

We want to write the equation of this circle in the standard equation. The standard equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

Solving

As we are given the center, we can plug its values into the equation.

Substitute 0 as h and 0 as k.

(x-0)² + (y-0)² = r²

This becomes:

x² + y² = r²

Now, we need to find r².

As the circle passes through (-8,4), we can use its values to help solve for r².

Substitute -8 as x and 4 as y.

(-8)² + (4)² = r²

64 + 16 = r²

80 = r²

Substitute 80 as r².

x² + y² = 80

User Death Metal
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.