Question

A student transformed the system of

equations shown below by multiplying
the second equation by a constant and
then adding the resulting equation to the
first equation.
x + 4y = 12
3x - y = 10

Answer 1

The answer to your problem is, 3x+6y=9 then -2x-4y=4

Explanation:

So first we are going to multiply the first equation by 2 and second equation by 3 and add it.

If there is both x and y terms gets cancelled then we can say there were no solutions at all.

Shown;

A) -2x+4y=4

-3x+6y=6

Which then becomes;

-4x + 8y = 8

-9x + 18y = 18

For, -13x + 26y = 26

B) 3x+y=12-

3x+6y=6

Which we then multiply first equation by 2 and second equation by 3

6x + 2y = 24

-9x + 18x = 18

For, -3x + 20y = 42

C)3x+6y=9

-2x-4y=4

Again multiply first equation by 2 and second equation by 3

6x + 12y = 18

-6x - 12y = 12

Which can equal to:

30

Which both x and y terms becomes 0.

Thus the anwer to your problem is, 3x+6y=9 then -2x-4y=4