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Y=-x^2-4x-4 find y coordinate

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If we substitute x = 2 into the equation y = -x^2 - 4x - 4, we get:

y = -(2)^2 - 4(2) - 4
y = -4 - 8 - 4
y = -16

Therefore, the y-coordinate of the point on the curve y = -x^2 - 4x - 4 when x = 2 is -16.
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