Question

Helppp this is so hard!,

Answer 1

Sure, I can help with that. The problem is asking for the area of a polygon composed of two rectangles and a right triangle.

The area of a rectangle is given by the formula length * width, and the area of a right triangle is given by the formula 1/2 * base * height.

Let’s calculate the areas:

For the first rectangle with dimensions 9ft by 13ft, the area is 9 * 13 = 117 square feet.

For the second rectangle with dimensions 10ft by 8ft, the area is 10 * 8 = 80 square feet.

For the right triangle with dimensions 28ft by 4ft, the area is 1/2 * 28 * 4 = 56 square feet.

Adding these areas together gives the total area of the polygon:

117 + 80 + 56 = 253 square feet

So, the area of the polygon is 253 square feet.

Answer 2

303.375 or 303 3/8

Explanation:

First, we can split the polygon into three smaller shapes: a triangle, a big rectangle, and a small rectangle. We will call them A, B, and C.

A:

Length: 28.25 - (3 + 13) = 28.25 - 16 = 12.25 (12 1/4)

Height: 10 + 9 = 19

Area: (12.25 * 19) / 2 = 232.75 / 2 = 116.375 ft

B:

Length: 3 + 13 = 16

Width: 10

Area: 16 * 10 = 160 ft

C:

Length: 3

Width: 9

Area: 3 * 9 = 27 ft

Now we have to add all three digits:

116.375 + 160 + 27 = 303.375 or 303 3/8

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Hope this helps :)