Answer:
The probability is 1/6.
Explanation:
Let's break down the problem into two separate events: rolling the number cube and tossing the coin.Event 1: Rolling the number cube
The number cube has 6 faces, numbered 1 to 6. Since it is fair, each face has an equal probability of landing face up.The favorable outcomes for rolling a number less than 3 are 1 and 2, as they are the only numbers that satisfy the condition "less than 3".So, the probability of rolling a number less than 3 is 2 out of 6, or 2/6, which can be simplified to 1/3.Event 2: Tossing the coin
The coin has 2 sides, heads and tails. Since it is fair, each side has an equal probability of landing face up.The favorable outcome for tossing a coin and getting heads is 1, as it is the only side that represents "heads".So, the probability of getting heads on the coin toss is 1 out of 2, or 1/2.Now, to find the probability of both events happening together (rolling a number less than 3 and getting heads on the coin toss), we multiply the probabilities of the two events:Probability of rolling a number less than 3 AND getting heads on the coin toss = Probability of rolling a number less than 3 * Probability of getting heads on the coin toss= 1/3 * 1/2= 1/6So, the probability that the number rolled is less than 3 and the coin toss is heads is 1/6.