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In a corn field in Nebraska, the net primary productivity is 150 grams/m²/day, and the respiration loss is 33.3%. The insolation energy is 645 calories/cm²/day. One gram of corn is equivalent to 400 calories. Find the gross productivity of the corn. b. Using NPP, calculate the efficiency of photosynthesis for the corn



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a. To find the gross productivity of the corn, we first need to calculate the amount of energy that is being produced by the corn. We can do this by multiplying the net primary productivity by the conversion factor, which is the number of calories per gram of corn:

Gross productivity = NPP / (1 - respiration loss) * conversion factor

Gross productivity = 150 g/m²/day / (1 - 0.333) * 400 cal/g

Gross productivity = 150 g/m²/day / 0.667 * 400 cal/g

Gross productivity = 89,955 cal/m²/day

b. The efficiency of photosynthesis can be calculated by dividing the net primary productivity by the amount of insolation energy that is available:

Efficiency = NPP / insolation energy

Efficiency = 150 g/m²/day / 645 cal/cm²/day * 1000 cm²/m² * 4 cal/g

Efficiency = 0.146%

Therefore, the efficiency of photosynthesis for the corn is 0.146%.
User Cale Sweeney
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