Question

What is the numerical value of Kc

for the following reaction if the equilibrium mixture contains 0.032 M
N2O4 and 0.24 M NO2?

N2O4(g)⇌2NO2(g)

Answer 1

The expression for the equilibrium constant (Kc) for the given reaction is:

Kc = [NO2]^2 / [N2O4]

Where [NO2] and [N2O4] are the molar concentrations of NO2 and N2O4, respectively, at equilibrium.

Substituting the given equilibrium concentrations into the expression for Kc, we get:

Kc = (0.24 M)^2 / (0.032 M) = 1.8 M

Therefore, the numerical value of Kc for the given reaction, when the equilibrium mixture contains 0.032 M N2O4 and 0.24 M NO2, is 1.8 M.