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Find the equation of the line that is purpendicular to y= -2/3x and contains the point (4,-8)

User Satoru
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1 Answer

5 votes

Answer:

y = 3/2x-14

Explanation:

The given line is y=-2/3x. So, the slope of the given line is -2/3.

Now, we have to find the perpendicular line to y= -2/3x passing through the point (4,-8).

The product of two perpendicular lines is -1.

m1.m2 = -1.

-2/3.m2= -1

m2 = 3/2

Now, we need to find the equation of the line passing through the point (4,-8) with slope 3/2.

The equation of slope-point form is (y-y1) = m(x-x1)

y-(-8) = 3/2 (x-4)

y+8 = 3/2x -6

Now, we have to add 6 on both sides.

y + 8 + 6 = 3/2x - 6 + 6.

y + 14 = 3/2x

y = 3/2x - 14.

User GoRoS
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