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Please help Due today!

Please help Due today!-example-1
Please help Due today!-example-1
Please help Due today!-example-2
User Gugguson
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1 Answer

4 votes

Answer: Wrote the answers below

Step-by-step explanation:

The balanced equation for Number 1 is:

Fe2O3(s) + 3H2(g) --> Fe(s) + 3H2O(l)

Step 1:

moles ratio of iron (III) oxide and hydrogen is 1:3

step 2:

work out mr (molar mass) of fe2o3: 111.68+ 48 = 159.68

moles of iron (III) oxide: 33.5g divided by 159.68 = 0.21 mol

Step 3:

1:3 ratio so 0.21 times 3 = 0.63 mol of hydrogen

Step 4:

mass of hydrogen = mol times mr

0.63 times 2 = 1.26g

mass of hydrogen = 1.26g or 1.27g depending on whether you used 1.00 or 1.01 for the mr of hydrogen

User Rishad Baniya
by
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